nlp_primitives.PunctuationCount¶
- class nlp_primitives.PunctuationCount[source]¶
Determines number of punctuation characters in a string.
- Description:
Given list of strings, determine the number of punctuation characters in each string. Looks for any of the following:
!”#$%&’()*+,-./:;<=>?@[]^_`{|}~
If a string is missing, return NaN.
Examples
>>> x = ['This is a test file.', 'This is second line', 'third line: $1,000'] >>> punctuation_count = PunctuationCount() >>> punctuation_count(x).tolist() [1.0, 0.0, 3.0]
- __init__()¶
Methods
__init__
()generate_name
(base_feature_names)generate_names
(base_feature_names)get_args_string
()get_arguments
()get_description
(input_column_descriptions[, ...])get_filepath
(filename)get_function
()Attributes
base_of
base_of_exclude
commutative
compatibility
Additional compatible libraries
default_value
Default value this feature returns if no data found.
description_template
input_types
woodwork.ColumnSchema types of inputs
max_stack_depth
name
Name of the primitive
number_output_features
Number of columns in feature matrix associated with this feature
return_type
ColumnSchema type of return
uses_calc_time
uses_full_dataframe